{"id":3913,"date":"2026-02-09T11:04:31","date_gmt":"2026-02-09T10:04:31","guid":{"rendered":"https:\/\/sti2tech.com\/?page_id=3913"},"modified":"2026-02-09T11:16:31","modified_gmt":"2026-02-09T10:16:31","slug":"bts-die-ci-td-n6","status":"publish","type":"page","link":"https:\/\/sti2tech.com\/?page_id=3913","title":{"rendered":"BTS – DIE CI – TD n\u00b06"},"content":{"rendered":"\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t\t
\n\t\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t
\n\t\t\t\t\t\t\t\t\t

TD n\u00b06 : Calcul d’imp\u00e9dances<\/h2>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t\t
\n\t\t\t
\n\t\t\t\t\t\t
\n\t\t\t\t
\n\t\t\t\t\t\t\t\t\t

Objectifs :<\/h3>
  • D\u00e9terminer<\/strong> une imp\u00e9dance totale<\/li>
  • Calculer<\/strong> la r\u00e9sistance d’un c\u00e2ble<\/li>
  • Calculer<\/strong> l’inductance d’un c\u00e2ble<\/li>
  • Connaitre<\/strong> le mod\u00e8le \u00e9quivalent d’une c\u00e2ble<\/li>
  • Calculer<\/strong> la r\u00e9actance totale<\/li>
  • R\u00e9diger<\/strong> les notes de calculs avec rigueur et assiduit\u00e9<\/li><\/ul>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
    \n\t\t\t\t\t\t
    \n\t\t\t\t\t
    \n\t\t\t
    \n\t\t\t\t\t\t
    \n\t\t\t\t
    \n\t\t\t\t\t\t\t\t\t

    Partie 1 – Rappel de cours<\/h4>
    1. Faire le sch\u00e9ma \u00e9quivalent du c\u00e2ble <\/strong>(source + imp\u00e9dance s\u00e9rie + r\u00e9cepteurs parall\u00e8les).<\/li>
    2. Faire le sch\u00e9ma \u00e9quivalent simplifi\u00e9<\/strong><\/li>
    3. Rappeler les expressions de R, X<\/strong>\u2097<\/strong> et Z.<\/strong><\/li>
    4. Calculer la r\u00e9sistance R <\/strong>du c\u00e2ble.<\/li>
    5. Calculer la r\u00e9actance inductive X<\/strong>\u2097<\/strong>.<\/strong><\/li>
    6. En d\u00e9duire l\u2019imp\u00e9dance \u00e9quivalente Z<\/strong>du c\u00e2ble.<\/li><\/ol>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t
      \n\t\t\t
      \n\t\t\t\t\t\t
      \n\t\t\t\t
      \n\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\"\"\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
      \n\t\t\t\t\t\t
      \n\t\t\t\t\t
      \n\t\t\t
      \n\t\t\t\t\t\t
      \n\t\t\t\t
      \n\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\"\"\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t
      \n\t\t\t
      \n\t\t\t\t\t\t
      \n\t\t\t\t
      \n\t\t\t\t\t\t\t\t\t
      Application :<\/h5>

      • Un c\u00e2ble en\u00a0cuivre<\/strong>\u00a0alimente\u00a0deux \u00e9quipements<\/strong>\u00a0connect\u00e9s en parall\u00e8le sur un r\u00e9seau\u00a0monophas\u00e9 230 V \u2013 50 Hz<\/strong>. Le c\u00e2ble mesure\u00a040 m<\/strong>\u00a0aller simple (soit\u00a080 m aller-retour<\/strong>).<\/p><\/li>

      • Sa\u00a0r\u00e9sistivit\u00e9<\/strong> est rho = 1,724*10^-8 Ohmm\u00e8tre . Son inductance lin\u00e9ique<\/strong> est 0,0004 mHenry\/m\u00e8tre. Section de c\u00e2ble 6 mm2.<\/p><\/li>

      • Calculer l\u2019imp\u00e9dance du c\u00e2ble et la chute de tension pour les \u00e9quipements ci-contre.<\/p><\/li><\/ul>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

        \n\t\t\t\t\t\t
        \n\t\t\t\t\t
        \n\t\t\t
        \n\t\t\t\t\t\t
        \n\t\t\t\t
        \n\t\t\t\t\t\t\t\t\t

        Partie 2 – Calcul de l\u2019imp\u00e9dance et de la chute de tension d\u2019un c\u00e2ble d\u2019alimentation<\/strong><\/h4>\n
          \n
        • V\u00e9rifier la chute de tension dans un c\u00e2ble en tenant compte de l\u2019imp\u00e9dance<\/strong>(r\u00e9sistance + r\u00e9actance).<\/li>\n
        • Un moteur triphas\u00e9 est aliment\u00e9 en 400 V \u2013 50 Hz<\/strong>par un c\u00e2ble en cuivre<\/strong> d\u2019une longueur de 100 m<\/strong>.<\/li>\n
        • Le courant absorb\u00e9 est de 30 A<\/strong>par phase.<\/li>\n
        • La section <\/strong>du c\u00e2ble est de 10 mm\u00b2<\/strong>.<\/li>\n
        • L\u2019inductance lin\u00e9ique<\/strong>du c\u00e2ble est de 0,0004 mH\/m<\/strong>.
          On admet une r\u00e9sistivit\u00e9 du cuivre<\/strong> : \n<\/em>

          <\/em><\/p><\/li>\n<\/ul>\n

          La chute de tension admissible est de 3 %<\/strong> de la tension d\u2019alimentation.<\/p>\n

          Travail demand\u00e9<\/strong><\/p>\n

            \n
          1. Calculer la r\u00e9sistance<\/strong> du c\u00e2ble .<\/li>\n
          2. Calculer la r\u00e9actance inductive<\/strong> .<\/li>\n
          3. En d\u00e9duire l\u2019imp\u00e9dance totale<\/strong> du c\u00e2ble .<\/li>\n
          4. Calculer la chute de tension r\u00e9elle<\/strong>  en triphas\u00e9.<\/li>\n
          5. V\u00e9rifier si la chute est inf\u00e9rieure \u00e0 la valeur admissible<\/strong> (3 % de 400 V).<\/li>\n<\/ol>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t
            \n\t\t\t
            \n\t\t\t\t\t\t
            \n\t\t\t\t
            \n\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\"\"\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<\/div>\n\t\t","protected":false},"excerpt":{"rendered":"

            TD n\u00b06 : Calcul d’imp\u00e9dances Objectifs : D\u00e9terminer une imp\u00e9dance totale Calculer la r\u00e9sistance d’un c\u00e2ble Calculer l’inductance d’un c\u00e2ble Connaitre le mod\u00e8le \u00e9quivalent d’une c\u00e2ble Calculer la r\u00e9actance totale R\u00e9diger les notes de calculs avec rigueur et assiduit\u00e9 Partie 1 – Rappel de cours Faire le sch\u00e9ma \u00e9quivalent du c\u00e2ble (source + imp\u00e9dance s\u00e9rie…<\/p>\n","protected":false},"author":4,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_kad_post_transparent":"","_kad_post_title":"hide","_kad_post_layout":"fullwidth","_kad_post_sidebar_id":"","_kad_post_content_style":"unboxed","_kad_post_vertical_padding":"hide","_kad_post_feature":"hide","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_kad_post_classname":"","footnotes":""},"folder":[22],"class_list":["post-3913","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/sti2tech.com\/index.php?rest_route=\/wp\/v2\/pages\/3913","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sti2tech.com\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/sti2tech.com\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/sti2tech.com\/index.php?rest_route=\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/sti2tech.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=3913"}],"version-history":[{"count":10,"href":"https:\/\/sti2tech.com\/index.php?rest_route=\/wp\/v2\/pages\/3913\/revisions"}],"predecessor-version":[{"id":3926,"href":"https:\/\/sti2tech.com\/index.php?rest_route=\/wp\/v2\/pages\/3913\/revisions\/3926"}],"wp:attachment":[{"href":"https:\/\/sti2tech.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=3913"}],"wp:term":[{"taxonomy":"folder","embeddable":true,"href":"https:\/\/sti2tech.com\/index.php?rest_route=%2Fwp%2Fv2%2Ffolder&post=3913"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}